# What is the probability of getting 2 kings assuming that the first one is not replaced?Answer:  4/52 * 3/51 = 1/13*1/17= 1/22

Example:  Conditional Probability:

Let's look at a standard deck of 52 playing cards.

Initial post:  What is the probability of getting 2 kings assuming that the first one is not replaced?

Answer:  4/52 * 3/51 = 1/13*1/17= 1/221

Initial post:  What is the probability of getting 2 kings assuming that the first one is replaced?

Answer:  4/52 * 4/52 = 1/13 * 1/13 = 1/169

Instructions

Initial Post:  Make up a similar example to the above problem using (a) with replacement and (b) without replacement. You may use playing cards, or a similar scenario, however be sure that you can represent both with and without replacement.  Flipping a coin 10 times is not appropriate because only represents the "without replacement" condition.

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